🧠 부족한 금액 계산하기

def solution(price, money, count):
    required_amount = sum(map(lambda x: x * price, range(1, count + 1)))
    return required_amount - money if required_amount > money else 0

function solution(price, money, count) {
  let requiredAmount = 0;
  for (let i=1; i<count+1; i++) {
    requiredAmount += i * price;
  }
  return Math.abs(Math.min(money - requiredAmount, 0));
}

func Abs(x int) int {
    if x < 0 {
        return -x
    }
    return x
}

func min(a, b int) int {
    if a < b {
        return a
    }
    return b
}

func solution(price, money, count int) int {
    requiredAmount := 0
    for i := 1; i < count + 1; i++ {
    	requiredAmount += i * price
    }
    return Abs(min(money - requiredAmount, 0))
}

def solution(price, money, count): 
    return abs(min(money - sum([price*i for i in range(1,count+1)]),0))

function solution(price, money, count) {
    const tmp = price * count * (count + 1) / 2 - money;
    return tmp > 0 ? tmp : 0;
}